Banking Pathway 2015 : Quant- Percentage (Study notes & Quiz)

In continuance to provide study notes(Short Tricks ) today we are Providing Notes on Percentage. Which is very crucial topic for SBI MainS(in DI), IBPS PO, IBPS Clerk, RBI assistant, IBPS RRB and many more competitive examinations.

Here we also Providing some concept clearing quiz for analysing yourself. Time management also very crucial part for gain good marks in exam. so use  wisely your time. Do not waste time on lengthy questions.

These Study notes are provided by one of our ardent BA reader Insomniac. We wish you good luck for future.

Percentage: 

The word defines itself Per means 1 upon something and Cent Is like Paise. In India we have 1 rupee = 100 paise

So per cent = 1/100 Part of something or %[ This sign even means 1/100] So if i say 20% of something Just multiply that something by 20/100 or 0.2

Like wise if is say 30% then it simply means i want to know 30/100th or 3/10th part value of something.

Why Do we Use percentage ?

Basically It is used for comparison.

Like If i say i got 400 marks in 10th and the other guy says that he got 600 marks in 10th. So Numerically He has got more marks than me  But does his score is relatively better than me ?

For that purpose we must know that He got 600 marks out of how many marks. Let's say he got 600 out of 1000. So his percentage marks will be 60%

And I got 400 out of 500. So my % marks will be 80%.

Now you can easily say that My marks are better because i am getting 80% and he is getting 60%.

How to calculate Percentage [ You all know it but just say I am telling it to myself :P ]

Well the simple formula is [Value/total value] * 100

For example A  Ring Contains 63 gm of Gold and total weight of ring is 70 gm. Find the percentage of Gold in the ring ?

So By the Formula [Value/Total Value]*100

[63/70]*100

[9/10]*100

90%.

% to Decimal Conversion or Fraction Conversion.

Just remember in Fraction Conversion we leave the fraction as it is without Converting Into Decimal. While in Decimal Conversion we first convert into fraction then Write the Decimal Value of that fraction.

Very easy You just have to dive by 100 nothing else.

For example 30% = 30/100 = 0.3

21% = 21/100 = 0.21

99% = 99/100 = 0.99

60% = 60/100 or 3/5 = 0.6

Case 1 [ Percentage of Quantity ]

Find the no. of male Students i.e boys, If there are 47% male students in the school and Total no. of students in the school is 1000.

As i said If you See anywhere % of something. Just convert the no. into it decimal value and multiply by that Something.

So in the above Question Boys are 47%[ Convert this into Decimal and you will get 0.47]  of 1000 [ Something] 

So what we gonna do friends we will just multiply it by 0.47 

So the no. of Boys will be 0.47*1000 = 470.

Lets See another Example.

A student scored 85% marks. Total marks are 400. How much marks did he score.

So a student got 85% marks out of 400

So again 85%[ Convert 85% in decimal i.e 0.85] of 400 [something]

So the answer will be 0.85*400 = 340 

so 340 is our answer.

Well they can also Change the Final Question.

Like in First Example they asked Find the no. of male students. They could have asked the no. of students that are not male.

So what we should do in that case. Nothing to worry my friend just do the usual job 47% are male that means that the rest 53% are not male now calculate 535 of 1000 that will be your answer i.e 530

Case 2 [ Inverse Case]

Now in the case 1 we were just asked to Find the % value something. But What if % value of something is given and we have to find the Total Value. ?

Now to worry below example will make it clear.

30% of a Number is 150. What is the number.

So after examining the question we can say that 30% of Some number is 150[ But we don't know yet what is the original number]

When we don't know about something Just Assign a variable to that value.

So we say that the Original Number is x

So as mentioned in the question 30% of x = 150

[ Convert 30% into decimal] 0.3*x= 150 

0.3x = 150

x = 150/0.3 

x = 500

So you see it's Quite easy.

Likewise Many Different Question can be formed on the same logic. Lets discuss 1

There are 200 girls in the class and girls and girls make up 25% of the class. Find the total No. of students in the class.

We don't know the No. of students so assume that no. of students is x

So what is given in the Question.

25% of Total Students in the class are Girls and Total Girls in the class is 200

lets just try convert above [English] Statement into mathematical Form

25% of x = 200

0.25*x = 200x = 200/0.25

x = 800

So total no. of students in the class = 800.

Case 3 - Percentage Change.[ Very Important For DI] 

The simple Way to put that is [( Change in Quantity/ Original Quantity) *100 ] Also [change in quantity = Final Quantity - Initial Quantity]

Note- The quantity in whose respect % change is asked is considered as the base By base i mean the original value in the above formula.

Let me make it clear to you with the help of Some Example.

The height of Nikhil some times ago was 160cm. Now his height is 200cm. Find the % change in his height?

So if we analyse the above question We can say that all we have to calculate is the % change in the height of  Nikhil with respect to his Earlier Height.

So now lets apply the formula here [( Change in quantity/ Original Quantity) * 100]

Which will be [{( 200-160)/160} * 100 ]

[{40/160}*100]

[(1/4)*100]

25%

So the % change in height = 25%.

Case 4- Use of Base Value and With Respect To Cases[ Very very Important For DI]

Suppose Salary of  Raman is 80,000 and Salary of Ved is 1,00,000. The questions are 

What per cent is the salary of Ved to that of Raman?

It's a very simple Question If you just know in whose respect you have to find the %.

Now in the above Question we have to find the % of ved salary with respect to ELF's Salary [ remember jiske respect me % nikalna hota hai Wohi base hota hai ] 

So here we have to find Ved's Salary with respect to Raman So we use the formula [ (Value/ In whose respect it is asked)*100]

So ved's salary in respect to Raman's salary will be [ (1,00,00/80,000)*100 ] = 125%

So VED's Salary is 125% of Raman's Salary.

If the question was just opposite.

Like What percent is the salary of Raman to that of Ved. (In this Question the Base will be Ved's Salary)

So lets just apply the formula [ Value/ In whose respect it is asked) * 100]

(80,000/1,00,000)*100 = 80%

So elf's salary is 80% of VED's Salary.

Case 5 - Product Constancy [ Most Important Because With it's Application You can also solve Questions related to Time and Work, Speed Time Distance,  Average etc. This Concept has a very huge application]

i - Speed*Time = Distance

ii- efficiency*time = work

ii- Length*breadth= area

iv- Average*No. of elements = Total value

v - rate*quantity = Expenditure

let me make you clear with an example.

The price of sugar is increased by 25% then by how much per cent should a customer reduce the consumption ( i.e quantity used) Of sugar so that he has not increase his expense on Sugar.

Just remember  If one factor of product constancy is increased by P% then the other factor will be decreased by [(p)/(100+p) * 100] To maintain the Product Constancy.

Now in the above Question The rate of sugar is increased by 25% So by how much % we should reduce the quantity to maintain the same expenditure 

Just apply the above formula [(p)/(100+p)*100]  = (25/125)*100 = 20%

Now It sound Simple but It is difficult to remind these formulas at the time of Solving Question So let me Give you simple method of learning this Formula.

Just Imagine In Your mind that the Quantity is 100. Ok

if the value is inreased by 25 % how much should the consumption be reduced.  

Now all you have to remember is [(How much % value is Increased/ What it becomes after increase) * 100 ]

No as i said In your mind the Quantity is 100. How much the value is increased in the above Question yeah 25% 

And how much it will become after 25% increase if the Quantity was 100 yeah That will be 125. So the answer will be 

(25/125)*100 = 20%

lets try again If the price of petrol is increased by 50%. By how much % the consumption be reduced so the expenditure remains same.

Just apply the formula How much increased = 50

What it will become after 50% increase = 150

% redcution required = (50/150)* 100 = 33.33%

In the same way you can also use the same formula for calculating just the opposite.

For Example If the price of Sugar is reduced by 20% by how much should the family increase it's consumption So the expenditure remains same?

How much % decrease ? = yeah it is 20%

What it will become after 20% decrease = Yeah 80 

So Increase required = (20/80)*100 = 25%

lets do one more question.

The price of petrol is reduced by 33.33% but how much % should a person increase his consumption so that His expenditure remains constant.

How much decrease = 33.33

What it will become after 33.33% decrease = 66.66

So % increase required = (33.33/66.66)*100 = 50%

The Length of Rectangle is Increased by 25% By what % the breadth be reduced so that are remains Constant?

Try Again How much Increase 25

What it becomes 125

% to be reduced = (25/125)*100 = 20%

Same way the Question of Time Speed Distance can also be solved But i will teach that when i will Explain Time Speed And Distance.

Case 6 - Increase or decrease In value to Get Back the Original Value.

Remember if a value P is increase by x % then we have to decrease the resultant value by 

[{ x/(x+100)} *100]% to get back the original value.

For Example Rocky's Salary is 1000rs and it Increased by 10%. How much % His salary must be Decreased So that he Gets His original Salary.

Apply the above Formula [{x/(x+100)}*100 = [ {10/(100+10)}*100] = 100/11 or 9.09090% 

In case of Decrease.

The formula will be [ {x/(100-x)}*100]%

Rocky Salary is 1000 and it is decreased by 10%. By how much % his salary must be increased so that he gets His Original Salary.

Apply the formula here [{10/(100-10)}*100]% = 100/9 % or 11.11% 

But Instead of Doing All this BS you can Also Apply My previous formula here.

Like Salary Increased 10. what wit will become 110.

How much it should be reduced = (10/110)*100 = 100/11 = 9.09%

Again Salary decreased = 10, What it will become 90.

So how much it should be increased to get the original salary = (10/90)*100 = 100/9 = 11.11%

CASE - 7 Concept of "by" and 'to"

Please note that there is very Big Difference between by and to.

Eg . The income is reduced BY 40% it means the New  Income 60% of the original value.

And If income is to 40% it means The new Income is 40% of the Original Value.

Case 8 - Consecutive Increase in Percentage.

Suppose the Salary of Sumit is first increase by 20% and Then again it's Increased by 20%.

What is the Total Percentage Increase in His Salary.

Now don't try to be smart here and just add 20% and 30%And say That it's 50% Increase-- THAT WILL BE TOTALLY WRONG.

Actuall let me make the Picture a Little bit Clear. What actually Happens in the case of Consecutive Increase and Decrease.

Now Just Suppose that The Salary of Sumit was 1000 Rs. it gets Increased by 20% so What it will become ? Yeah you are right 1200rs.

Now When it is Again Increased by 30% Then we are Calculating that 30% increase on 1200RS ans not on 1000 So the Inrease will be 30% of 1200 which will be 360. So increased salary will be 1200 + 360 = 1560.

Now are two Shortcut Methods Here.

1st Simple Multiplication.

When I say Something is increased by 20% It means It's Value Is increased by 20 % or It's Total value is 120% of the original Value Ok ? 

Like 100 is incresed by 20% That means it's final value will be 100 + 20% of 100 = 100 + 20 = 120.

So if  Sumit  Salary is Increased By 20% that the Value will be 100*1.2.

And If it's Again increased by 30% then the value will be 100*1.2*1.3 = 100*1.56 = 156.

Total increase = 56.

Percentage Increase = 56%

2nd Method Formula Approach.

Well the formula is [x + y + (xy)/100]% [Note this formula works only when there is 2 increases]

Now apply the formula in above Question you will get 20 + 30 + (20*30)/100 = 50 + 600/100 = 50 + 6 = 56%

Same Sumit's Salary is 1000rs and if it's asked the Salary of Sumit is Increased First by 20% then 30% and then again by 40% then what will be Total Increase and Final Salary.

It's Pretty simple now 1000*1.2*1.3*14 = 2184 

That's the final Salary and % inrease = [(2184-1000)/1000]*100 = (1184/1000)*100 = 118.4% 

Some Similar Questions Are like.

The Side of Square is Increased by 10% what will be the increase in Area. 

So Just Let The Value of Eaxh side is x, If it's Increased by 10% Then it will become 1.1x

As You know are = Side*side

So Initially The Area without Increase Would Have been x*x = x^2

After Increase the Area will be 1.1x*1.1x = 1.21x^2

So total % increase in area will be 21%.

Case -9 Consecutive Increase and Decrease Simultaneously

In the last case we saw the case of % increase but now we will learn how to solve when there is a consecutive Increase and as well As decrease.

It's same as the last example.

Sumit's Salary is 1000rs Suppose the salary of Megamind was first Increased by 30% and Then decreased by 20%. What will be final Increase or Decrease in His Salary.

Just do The same Thing 30% increase means 1000*1.3

And then 20% Decrease mean 0.8times [ remember we have to decrease here and 20% decrease means 0.2 Point decrease] 

So total decease = 1000*1.3*0.8 = 1040.

Final Increase = 40RS

% Increase will be 4%.

With Formula.

Remember the formula x + y + (xy)/1000

Same formula can be used here But remember Increase means +ve Sign and decrease means -ve sign,

So apply here now 30 - 20 + (30)(-20)/100 = 10 - 600/100 = 10 - 6 = 4%.

Thank you Insomniac..

Quiz :

Time : 5-6 minutes.

1.  Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them?

A) 42, 36

B) 44, 39

C) 42, 33

D) 44, 37

E) None of these.

2. A fruit seller had some oranges. He sells 40% oranges and still has 420 oranges. How many oranges he had originally?

A) 690

B) 700

C) 720

D) 745

E) None of these.

3.  A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?

A) 45(6/11) %

B) 45(7/11) %

C) 45(5/11) %

D) 46(5/11) %

E) None of these.

4.  In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, what was the number of valid votes that the other candidate got?

A) 3690

B) 2700

C) 5720

D) 4745

E) None of these

5.  A student has to obtain 33% of the total marks to pass. He got 125 marks and failed by 40 marks. The maximum marks are

A) 600

B) 700

C) 520

D) 500

E) None of these.

6. A housewife saved Rs. 2.50 in buying an item on sale. If she spent Rs. 25 for the item, approximately how much percent she saved in the transaction ?

A) 6 %

B) 7 %

C) 10 %

D) 9(1/11) %

E) None of these.

7. A pipe X is 30 meters and 45% longer than another pipe Y. find the length of the pipe Y?

A) 600/29 meter

B) 37.25 meter

C) 20 meter

D) 50 meter

E) None of these.

8. On my sister’s 15th birthday, she was 159 cm in height, having grown 6% since the year  before. How tall was she the previous year ?

A)156 cm

B) 150 cm

C) 155 cm

D) 172 cm

E) None of these

9. Sumit got 30% of the maximum marks in an examination and failed by 10 marks. However, Sujith who took the same examination got 40% of the total marks and got 15 marks more than the passing marks. What were the passing marks in the examination?

A) 96 

B) 150

C) 75 

D) 85 

E) None of these

10. 30% of the men are more than 25 years old and 80% of the men are less than or equal to  50 years old. 20% of all men play football. If 20% of the men above the age of 50 play football, what percentage of the football players are less than or equal to 50 years?

A) 60 %

B) 50%

C) 80 % 

D) 85 %

E) None of these

Answers:

1. C
2. B
3. C
4. B
5. D
6. D
7. A
8. B
9. D
10.C

Daily GK Update - 3rd July2015

1. Govt releases socio-economic and caste census for better policy-making

i. The socio-economic and caste census (SECC) 2011 on Friday painted a grim picture of rural India, indicating that one out of three families living in villages is landless and depends on manual labour for livelihood.

ii. The SECC 2011, also the first paperless census conducted on hand-held electronic devices by the government, said 23.52% rural families have no literate adult above 25 years, suggesting a poor state of education among rural masses.

iii. The census, carried out in 640 districts under the aegis of the rural development ministry, was released jointly by finance minister Arun Jaitley and rural development minister Chaudhary Birendra Singh.

iv. According to the census, there are a total number of 24.39 crore households in the country, of which 17.91 crore live in villages. Of these, 10.69 crore households are considered as deprived.

2. Nationwide Mobile Number Portability goes live

i. The countrywide Mobile Number Portability (MNP) has become a reality today. This means mobile subscribers can now keep their existing mobile phone numbers even while shifting between states and circles.

ii. The move lays the first stone for the government's 'One nation, One number' plan and is sure to benefit millions of people across the country.

iii. Earlier, the deadline to rollout full MNP was May 2, 2015. This was, however, extended by two months after the Cellular Operators Association of India asked for an extension from the telecom department.

iv. With about 3 million intra-circle MNP requests every month, more than 157 million subscribers have ported to other operators as of April, according to Trai data.

3. Airbus to build military choppers in India with Mahindra

i. Europe's Airbus Group and India's Mahindra Group have struck a deal to build helicopters jointly as they bid to win an expected wave of orders from the country's armed forces, the companies said in a statement on Friday.

ii. The two groups will form a joint venture in the coming months, aiming to become the first private manufacturer of helicopters in India, the statement said. It did not say how much the two will invest. 

iii. India is in the midst of a huge upgrade of its armed forces — analysts forecast it will spend $250 billion over the next decade — and Prime Minister Narendra Modi wants to encourage more indigenous manufacturing to end India's position as the world's largest arms importer.

iv. Airbus Helicopters, part of Airbus Group, is joining forces with Mahindra after talking to several Indian companies that are investing hundreds of millions of dollars to capitalise on the government's push to build arms at home.

4. SBI launches initiative to speed up home loan applications 

i. Country's largest lender State Bank of India today launched an initiative to provide doorstep services and expedite home loans application process. 

ii. The initiative known as 'Project Tatkal' will help get the loan within 10 days after receipt of application form and relevant supporting documents, the bank said in a release.

iii. The implementation will be done at large centres with sizable home loan business.

iv. The bank has also recently introduced an online customer acquisition solution (OCAS) for instant e-approval of home loan applications.

5. Indian-American professor R Paul Singh named for 2015 World Agriculture Prize laureate

i. R Paul Singh, Indian-American professor has been selected for 2015 World Agriculture Prize laureate.

ii. The award was announced at the annual Global Confederation for Higher Education Associations for Agriculture and Life Sciences (GCHERA) conference held at the Holy Spirit University of Kaslik, Lebanon.

iii. Singh is known for niche research areas of agricultural sector such as freezing preservation, energy conservation, post-harvest technology and mass transfer in food processing.

iv. He had earned a bachelor’s degree in agricultural engineering form Punjab Agricultural University. He had completed his doctorate from Michigan State University, US.

6. Indian-American teacher Darshan Jain receives US Presidential Award

i. Darshan Jain, an Indian-American teacher has been selected for prestigious Presidential Award for Excellence in Mathematics and Science Teaching.

ii. He was named for the award by President Barack Obama along with 107 Mathematics and Science teachers across US. All of them were chosen for shaping America’s success through their passion for Math and Science.

iii. Presently Darshan Jain is director of mathematics at Adlai E. Stevenson High School in Lincolnshire, Illinois. Previously, he had taught mathematics at this institute for eight years.

iv. US Presidential Award is awarded annually to outstanding science and mathematics teachers from across US from K-12 (kindergarten through 12th grades). The award carries monetary prize of US 10000 dollars.

7. Union Government launches web portal for issuing green clearance Category B projects

i. Union Government has launched a web portal for online submission of applications for environment clearance by State Environment Impact Assessment Authorities (SEIAA) for Category B projects.

ii. It was launched by Union Minister of State for Environment, Forest and Climate Change Prakash Javadekar in New Delhi on the occasion of Digital India Week. Soon after the launch of the web portal, nineteen states instantly have joined it.

iii. The environment clearance web portal raises the levels of transparency and accountability as the clearances will be monitored and carried out effectively on a real time basis. It will also help to reduce pendency for maintaining the rigours of Environment Clearance process.

iv. It should be noted that applications for Environment Clearances under Category ‘B’ projects under EIA notification, 2006 comes under State government for approval purpose.

www.bankersadddaa.com

SBI Mains Date Released

Dear Readers,

SBI has declared the date for the Mains exam for the post of PO. The exam date is 26th July 2015. The admit cards will get released on 13th July 2015.

Now it is more important for you to start the preparations and get in a rhythm. The result of the preliminary exams can be expected soon. So get ready for the Main battle with SBI.

To View the notice : Click Here

SHORT TRICKS TO REMEMBER DAYS

This is in continuance to the previous series provided by @k$. This is one of the important topics he has covered.

4) April: 

1) 2 april -Autism awareness day in short (AADami)/World autism day

2) 7 april- world health day

3) 21 april- Civil service day

4) 22 april- Earth day

5) 24 April- National Panchayati Raj day

No. Of days=5

Subject-chaar (april is 4th month) ka paanch

Trick with story-

2 AADamiyo be acche helath ke sath (7) 21 baar civil service ka exam diya or ve do do (22) bar is dharti (earth) par pass hue or end me 24 vi baar me unhe Panchayat vibhag mila. (Hard work pays off)

5) May:

1) 1 may- international labour day

2) 3 may- world press freedom day

3) 11 may- National technology day

4) 21 may- Anti- terrorism day/death of Rajiv gandhi

5) 31 may- Anti-Tobacco day

No. Of days=5

Subject- Paanch ka panch

Trick with story-

1 (ek) Rajiv naam ka labour tha jisey 3 press (stri) free me miley the jo 11vi sadi ki technology se bane the par 21vi sadi me kuch terrorist ne Rajiv ko mar kar usey 31 rupaye me Tobacco company ko bech diya.

6) June :

1) 5 june- World environment day ( everyone knows)

2) 21 june- World Yoga day ( latest hai sb jante hai)

7) July :

1) 1 july - National Doctor's day

2) 11july - world population day

No. Of days- 2

Subject- Sath(7)-sath (7) 2 kadam chale---

Trick with Story-

1 doctor ne san 20'11' ke population ko control kiya.

www.bankersadddaa.com

Banking Pathway 2015: Quant Short tricks (Time & Work)

Time and Work is a very easy topic and at least 2 Questions are asked from this topic in Any Exam whether it's Clerk or PO or SSC.What actually the Time and Work Topic is all about? In simple words It's how much time a person will take to Complete a Given Work.

Here we are providing some cases of time and work and efficient method to solve it. Hope this would be helpful to all aspirants.

These Tricks are shared by one of the our ardent BA reader Insomniac.We wish you good luck for your future.

Note -: In conventional Method work is always treated as 1

Example: So if I say that a person can complete a work in 15 days that means he will do 1/15 work in one day, It's simple maths.

Now another person does the same work in 30  days. So he will do 1/30 work in 1 day.

Now if i ask in how many days they will complete the work together. What we gonna do is Add their 1 day of work

 like 1/15 + 1/30 = (2+1)/30 = 3/30 = 1/10 

Now this 1/10 we got is actually their 1 day work, So if they do 1/10 work in one day then it's simple they will complete the whole work in 10 days.

Now that was the conventional method and I believe that you all know how to solve Questions through Conventional method.

So now lets move on to the Faster method i.e efficiency method.

In efficiency method the Work is not treated in numerical value, Like in Conventional method the work is 1 but here the work is treated as percentage.

So by common sense the work is always treated as 100%

So when i say a person completes a work in 15 days it means he will do 100/15 % work in 1 day i.e 6.66% work in 1 day

If another person does the work in 30 days that means he will do 3.33% work in 1 day.

And together they will do 6.66 + 3.33 = 9.99 or 10% work in one day So in how many days they will do the complete work, that will be 100/10 = 10 days.

Now it may sound difficult That we have to convert Each value in % but don't worry you don't have to convert each value, You just have to learn all the values till 1/30 and then it will be a cakewalk.

Now we will take Some standard Cases Of time and work and you all are free to ask any problem if you have in any case.

Case 1 - A does a work in X days, B does a Work in Y days In how many days they will complete the work.

Question- A completes the work in 10 days and B completes the work in 15 days In how many days they will complete the work.

Conventional Method 

Work done by A in 1 day = 1/10

Work Done by B in 1 day = 1/15

Work done By A & B together in 1 day = 1/10 + 1/15 = (3+2)/30 = 5/30 = 1/6

As A & B Completes 1/6 work in one day So they will complete the whole work in 6 Days.

Efficiency method.
Efficiency of A =100/10 = 10% 

Efficiency of B = 100/15 = 6.66%

Efficiency of A & B Together = 10+ 6.66 = 16.66%

So the time taken by A & B together to Complete the work will be 100/16.66 = 6 Days.

Case -2 A can do a work in X days and B can do it Y days, In how many days the work is completed if they work alternatively Started by A.

Now in these type of question the person are not actually working together, what happens in this type of question is that A works for 1 day and then on 2nd day B work and on 3rd again A work and on Fourth again B works and so on till the work is completed.

For example A can do a work in 10 days B can do it 15 days and how many days they will finish it if The work is started by A

So again work done by A in one day = 1/10

 ''     ''          ''        ''      ''  B      ''      ''      = 1/15

Now the work done by Togther will be = 1/10 + 1/15 = 1/6 [ Note now this 1/6 work is not done by them in 1 day but in 2 days Actually, See A worked for 1 day and did 1/10 work on the second day B worked and finished the 1/15 work So in total 2 days they did 1/6 work]

So in 2 days they did 1/6 work so in how many days they will complete the whole work, Simple 12 days.

Efficienecy Method

A's Efficiency = 10%

B's Efficiency = 6.66%

A + B Efficiency = 16.66%

Work done by A and B in 2 days [ remember 2 days because they are not working together but working alternatively] = 16.66%

So time taken by them to complete 100% work = 100/(16.66 = 6 [ but always remember multiply this by 2, Beacause 16.66% work is done by them in 2 days and not in 1 day.

So The answer will be 6*2 = 12 days.

Case 3: A can do a work in X days, B can do the work Y days and A leaves after working Z days.

Question- A can do a work in 10 days and B can do it in 15 days, A works for 2 days and then leaves, In how many days will the work be completed?

Now here we can se that A leaves after 2 days that means A and B only worked for 2 days and the remaining work is done by B alone.

So first we have to calculated the work done by A and B together in 2 days.

So work done be A in 1 day = 1/10

""   "         "        "  B "  "   "     = 1/15

Work done by A & B together is 1 day = 1/10 + 1/15 = 1/6

Work done by A & B together in 2 days = (1/6) * 2 = 1/3

So remaining work = 1 - 1/3 = 2/3

Now this 2/3 work has to be done by B alone.

So it takes 15 days for B to do Complete work, How much time it will be taken by B to do 2/3 work ? So it will be 15*(2/3) = 10 days

So the work will be completed in 2 + 10 days = 12 days

Efficiency method 

A's efficiency = 10% 

B's Efficiency = 6.66%

Total a+b = 16.66%

work done by A and B together in 2 days = 16.66*2 = 33.33%

Work remaining = 66.66%

time taken by B to complete 66.66% work = 66.66/6.666 = 10 days

Total time = 10+2 = 12 days

Case 4

A can do a piece of Work in 10 days and B can do it in 15 days, In how many days will the work be completed if B leaves 2 days before the completion on work.

Now in this question B leaves before 2 days

Together they can do the work in what = 1/10 + 1/15 = 1/6

That means 6 Days.

That means Together they could have completed the work in 6 days but B works only till 4th day and The remaining work will be done by A alone

So they worked together for 4 days in all So work done by them in 4 days = (1/6)*4 = 4/6 = 2/3

remaining work = 1/3 

Now this 1/3 work will be done by A alone 

Now A can do the complete work in 10 days, So the time taken by him to do 1/3 work = 10 * (1/3) = 10/3 days or 3.33 days

So total time taken = 4+ 3.33 days = 7.33 days

Efficiency method

A's efficiency = 10%

B's efficiency = 6.66%

Total = 16.66%

Work will be completed in 6 days

Work done in 4 days = 66.66%

remaining = 33.33%

A will complete the remaining in = 33.33/10 = 3.33 

Total = 4+3.33 = 7.33

Case 5: A can do a Work in X days B can Do it in Y days, In how many days The work will get completed if B leaves 2 days before the actual completion of work.

Question: A can do a work in 10 days B can do it in 15 days, In how many days The work will get completed if B leaves 2 days before the Actual Completion of Work.what is the difference between this Actual completion of work and Completion of Work?

See in last example the work was supposed to get completed in 6 days, So we just Solved the question taking into consideration that B leaves 2 days before the completion of work i.e B worked for 4 days and the rest 2 days work was don by A alone and Completes that work in 3.33 days Total 7.33 days.

So if i ask In this question If B left 2 days before the actual completion then it means B should have left on 5.33 days Got it ?

Now back to the question.

Now just imagine that the work gets completed in x days.

So A would work for x days[ A works for the whole time ]

And B would work for x-2 days[ because B left 2 days before the actual completion of work]

So now According to Question

x/10 + (x-2)/15 = 1 [ Beacuse work is always one ]

(3x+2x-4)/30 = 1

5x -4 = 30

5x = 34

x = 6.8 days.

So the work will be completed in 6.8 Days.

It can also be asked That after how many days B left, So the answer would be Simple 6.8 - 2 = 4.8 days

Efficiency Method

A's Efficiency = 10%

B's Efficiency = 6.66%

Let the no. of days be x 

so Accordring to question

10x + 6.66(x-2) = 100[ Work is always 100% in efficiency method ]

10x + 6.66x - 13.33 = 100

16.66x = 113.33

x = 113.33/16.66 = 6.8 

Answer = 6.8 days

Haryana Police Recruitment 2015 HPRB Constable 13200 News

HPRB Haryana Govt online to that 12th pass favorable seeker to apply for Haryana Police Constable Vacancy latest news 2015-16. applicant now get application form link to visit for Haryana Police Recruitment 2015.if you know how to fill the syllabus of Haryana police constable then visit hprbonline.in which is now started  from 1st week of July. See the below ezine article for complete information related to Haryana Police Constable bharti.

Haryana hprb police constable online applications are invited in the prescribed performs through website www. Hprbonline.com or www.hprbonline.in from eligible candidates for various posts of Group C and D in Haryana Police as detailed below.  The applications will be filled July to August as per Haryana Police Constable Notification 2015 after which the link will be disabled. The candidates are advised to apply online well in time without waiting for last date of submission of online application. No offline application form or copy of downloaded application form will be accepted by this office.

Haryana HPRB is the only recruitment board same as upprpb of UP Police that that conducts all types of Physical Efficiency Test, Medical test and written test examination as per concerned exam date. If you want to apply those govt jobs after 12th pass then it is correct Haryana Police Recruitment Board always welcomes its prospective career aspect candidates for enrollment into Haryana Police vibhag bharti.

HPRB Constable Recruitment 2015 hprbonline.in

Name:  Haryana Police Recruitment Board

Job: Police both Lady and Men

Total Vacancies: 13200

Eligibility Criteria for Haryana Constable Vacancies

Educational Qualification: candidates must have completed Metric pass 12th class or 10+2 from any recognized university. Knowledge of Hindi reading and writing.

Selection Procedure:  skilled tests in relevant trade and interview indicating date and place of skill tests/ interview

Age Limit: candidates should have between 18 years to 25 years of age

Salary and grade pay: Rs. 5200/- to Rs. 20200/- with Rs. 2400/-

How to apply for Haryana Police constable:-

i) The candidates should visit website Link 1 or Link 2, after applying online a registration No. of candidate and ID No. will be generated.

ii) Take printout of registration No. and ID No. for future reference to application and for reprinting of online filled application form and e-challan form.

Important Dates will published in mid July